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8x^2-49x+68=0
a = 8; b = -49; c = +68;
Δ = b2-4ac
Δ = -492-4·8·68
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-15}{2*8}=\frac{34}{16} =2+1/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+15}{2*8}=\frac{64}{16} =4 $
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